3.2.5

Diffraction Gratings

Test yourself

Diffraction Grating Equation

The pattern produced by a diffraction grating can be described by the diffraction grating equation.

Illustrative background for EquationIllustrative background for Equation ?? "content

Equation

  • Diffraction gratings produce a pattern which is described by:
    • dsinθ=nλd\sin\theta = n\lambda
      • Where d is the distance between slits in the grating, θ is the angle between the maximum and the zero order line, λ is the wavelength of incident light, and n is the order of the maximum.
Illustrative background for Slit spacingIllustrative background for Slit spacing ?? "content

Slit spacing

  • A diffraction grating is made of many slits.
  • If there are 1000 slits per metre, then slit spacing is 1/1000 metres.
  • In general, if there are x slits per metre, then the slit spacing is 1/x metres.
  • This gives the value of "d".
Illustrative background for OrdersIllustrative background for Orders ?? "content

Orders

  • The variable "n" stands for the order of the maximum.
  • Knowing d and λ lets us predict the angle of the central maximum.
  • The central maximum is the zero order. "n" is zero.
  • This implies that θ is zero. This is what we expect.
  • The first order maximum will have n = 1, the second order maximum will have n = 2, and so on.
Illustrative background for Not all orders existIllustrative background for Not all orders exist ?? "content

Not all orders exist

  • Remember that sin θ cannot be greater than 1.
    • If you are using the equation and find that sin θ is larger than 1, the order you are looking at must not exist.
Illustrative background for ConclusionsIllustrative background for Conclusions ?? "content

Conclusions

  • As we increase λ, sin θ increases so θ increases. This means the pattern becomes more spread out.
  • If we increase the distance between slits, d, sin θ decreases so θ decreased. This means the pattern becomes less spread out.

Derivation of Grating Equation

You need to know how to derive the diffraction grating equation.

Illustrative background for Step 1 - producing coherent sourcesIllustrative background for Step 1 - producing coherent sources ?? "content

Step 1 - producing coherent sources

  • Light enters the grating as parallel rays.
  • It diffracts through each slit.
  • The slits then act as coherent (in phase) and monochromatic (same wavelength) sources of light.
  • These diffracted waves then interfere with each other to produce the pattern.
Illustrative background for Step 2 - angle to 1st orderIllustrative background for Step 2 - angle to 1st order ?? "content

Step 2 - angle to 1st order

  • The 1st order maximum happens at an angle such that the path difference between two sources is one wavelength, λ (for constructive interference).
  • Let's call this angle θ.
Illustrative background for Step 3 - create triangleIllustrative background for Step 3 - create triangle ?? "content

Step 3 - create triangle

  • We create a triangle as shown above.
  • We know the distance between the two slits is d.
  • We know the path difference is λ.
  • We know the angle θ by geometry.
Illustrative background for Step 4 - use trigonometryIllustrative background for Step 4 - use trigonometry ?? "content

Step 4 - use trigonometry

  • Using trigonometry, we can see that:
    • path difference =λ=dsinθ=\lambda = d \sin\theta
Illustrative background for Step 5 - generalise for all nIllustrative background for Step 5 - generalise for all n ?? "content

Step 5 - generalise for all n

  • We know that maxima always occur for when the path difference is a whole number multiple of λ (constructive interference).
  • Therefore, we can generalise the equation so that path difference = nλ
    • nλ=dsinθn\lambda = d \sin \theta

Applications of Diffraction Gratings

Diffraction gratings are very useful for physicists.

Illustrative background for Analysing lightIllustrative background for Analysing light ?? "content

Analysing light

  • Diffraction gratings can be used to separate wavelengths in light from different substances.
  • The wavelengths present can help us learn new things about the substance being tested.
Illustrative background for Atomic spacing in crystalsIllustrative background for Atomic spacing in crystals ?? "content

Atomic spacing in crystals

  • Atoms in a crystal can act like a diffraction grating, with little gaps for light to pass through.
  • We can find the spacing between the atoms in the crystal by looking at how X-rays diffract through the crystal.

Jump to other topics

1Measurements & Errors

2Particles & Radiation

3Waves

4Mechanics & Materials

5Electricity

6Further Mechanics & Thermal Physics (A2 only)

7Fields & Their Consequences (A2 only)

8Nuclear Physics (A2 only)

9Option: Astrophysics (A2 only)

10Option: Medical Physics (A2 only)

11Option: Engineering Physics (A2 only)

12Option: Turning Points in Physics (A2 only)

Go student ad image

Unlock your full potential with GoStudent tutoring

  • Affordable 1:1 tutoring from the comfort of your home

  • Tutors are matched to your specific learning needs

  • 30+ school subjects covered

Book a free trial lesson