2.5.7

Buffer Solutions (A2 Only)

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Buffer Solutions

Buffer solutions oppose small changes in pH.

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What is a buffer solution?

  • A buffer solution is a solution that opposes pH changes.
    • This means that if you add acid, the buffer solution removes it to keep a constant pH.
    • In reality, they don't keep a completely constant pH, but they reduce the size of any changes.
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How does a buffer solutions work?

  • Buffers work through changes in equilibria.
  • An acidic buffer will contain a weak acid and a salt of the weak acid.
    • E.g. methanoic acid and sodium methanoate.
  • The important equilibrium is:
    • CHOOH ⇌ CHOO- + H+
  • As you have sodium methanoate, you have lots of CHOO-.
  • According to le Chatelier’s principle, this will remove lots of H+ from solution to reduce the concentration of CHOO-.
    • This means you have a lot of un-ionised methanoic acid
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Adding acid to an acid buffer

  • If you add acid to this acid buffer solution, then the methanoate ions will react with the hydrogen ions and remove them.
    • This will reduce any change in pH.
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Adding a base to an acid buffer

  • If you add a base to the acid buffer solution, the hydrogen ions will react with it and neutralise it.
  • The un-ionised methanoic acid will ionise to produce more H+ ions and this will reduce the pH change.
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Basic buffers

  • A basic buffer has a pH above 7 and works on a similar principle.
  • A good example is ammonium hydroxide.
  • The equilibrium for this reaction is:
    • NH3 + H2O ⇌ NH4+ + OH-
    • Adding base shifts the equilibrium left to remove base.
    • Adding acid shifts the equilibrium right to remove the acid.

Calculations of Buffer Solutions

Buffer solutions have a specific pH, which can be calculated.

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Assumptions

  • All you need to know to calculate the pH of a buffer solution is its Ka.
  • You need to make a couple of reasonable assumptions:
    • That the salt is fully dissociated.
    • That the acid is pretty much un-ionised.
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Method

  • Write down the equation for Ka:
    • Ka = [H+][A][HA]\frac{[H^+][A^-]}{[HA]}
  • Rearrange it for the hydrogen ion concentration:
    • [H+] = Ka × [HA][A]\frac{[HA]}{[A^-]}
  • We assume the salt is fully dissociated, so [A-] is just the inital salt concentration.
  • We assume the [HA] is un-ionised, so that’s just the initial acid concentration.

Jump to other topics

1Physical Chemistry

2Physical Chemistry 2 (A2 Only)

3Inorganic Chemistry

4Inorganic Chemistry 2 (A2 Only)

5Organic Chemistry 1

6Organic Chemistry 2 (A2 Only)

6.1Optical Isomerism (A2 Only)

6.2Aldehydes & Ketones (A2 Only)

6.3Carboxylic Acids & Esters (A2 Only)

6.4Aromatic Chemistry (A2 Only)

6.5Amines (A2 Only)

6.6Polymers (A2 Only)

6.7Biological Organic (A2 Only)

6.8Organic Synthesis (A2 Only)

6.9NMR Spectroscopy (A2 Only)

6.10Chromatography (A2 Only)

6.11A-A* (AO3/4) - Organic 2

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