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Turning Points of Graphs

The turning point of a graph is any coordinate on a graph where the gradient = 0. Another way to say this is that the derivative of the graph = 0 or that the gradient of the graph = 0.

Turning points

Turning points

  • Once you have found the derivative of a graph, f'(xx), you can find the xx coordinate of a turning point by making f'(xx) = 0.
  • When f'(xx) = 0, the rate of change of the function is equal to zero.
  • It is called a turning point because the graph often changes direction at f'(xx) = 0.
Example

Example

  • If f(xx) = xx2 − 2xx
    • f'(xx) = 2xx − 2
  • The turning point is when f'(xx) = 0
    • So, 0 = 2xx − 2
    • Solve for xx to find xx = 1
Example cont.

Example cont.

  • Find the yy-coordinate by substituting in the value of xx = 1 into f(xx).
    • f(1) = 12 − (2 × 1)
    • f(1) = −1
  • So the coordinate of the turning point of f(xx) = xx2 − 2xx is (1, −1).

Maxima & Minima

You can categorise turning points as a maximum or a minimum. Maxima and minima are the plurals of maximum and minimum.

Maxima & minima

Maxima & minima

  • A turning point is a local maximum if it is a high point when the graph is turning.
  • A turning point is a local minimum if it is a low point when the graph is turning.
The second derivative

The second derivative

  • You can find out if a turning point is a local maximum or local minimum using the second derivative.
  • The second derivative is found by differentiating the derivative.
    • We can write the second derivative of f(xx) is f''(xx)
    • We can write the second derivative of yy as d2ydx2\large\frac{d^2y}{dx^2} or yy''.
Local maximum or local minimum

Local maximum or local minimum

  • Once you have the xx value of the turning point, you can find out if it's a local maximum or a local minimum by substituting the xx value into the second derivative.
    • If the second derivative is less than 0, then it is a local maximum.
    • If the second derivative is greater than 0, then it is a local minimum.
Example

Example

  • f(xx) = xx3 + 6xx2 + 12 has a turning point at (0, 12). Is this a maximum or a minimum?
    • f'(xx) = 3xx2 + 12xx
    • And f''(xx) = 6xx + 12
    • Then substitute in the xx coordinate of the turning point into f''(xx).
    • f''(0) = (6 × 0) + 12 = 12
    • f''(xx) is positive at xx = 0 so the turning point at (0, 12) is a local minimum.
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