6.6.4

Oxidation States & Equations

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Oxidation States and Redox

Oxidation states are crucial tools for understanding redox reactions.

Oxidation states

Oxidation states

  • An oxidation state shows how many electrons an atom has gained or lost.
  • The concept of oxidation state is related to electronegativity.
    • Electronegativities can be used to work out oxidation states.
  • There are a set of rules to assigning oxidation states - these will be unpacked in the next slide.
Rules

Rules

  • To assign oxidation states in a compound with multiple elements, we pretend every bond is ionic (even when they're definitely not)!
    • We ask the question 'which element is going to take the electron pair?'
    • The answer is, the most electronegative one!
  • This gives us our first rule:
    • In a compound with fluorine, fluorine's oxidation state is always -1.
Oxygen

Oxygen

  • The oxidation state of oxygen is always -2.
    • Unless you have a compound of oxygen and fluorine. The fluorine rule takes priority.
    • Another exception is in a peroxide (e.g. Na2O2).
Hydrogen

Hydrogen

  • Hydrogen always has an oxidation state of +1.
    • Except in metal hydrides e.g. NaH, where it is -1.
The rest

The rest

  • In a compound ion, the overall oxidation state is equal to the charge on the ion.
  • In a simple ion, the oxidation state is just the charge on the ion.
  • In a pure element, the oxidation state is zero. This includes atoms like He, but also molecules like H2.
  • Oxidation states are commonly represented by Roman numerals e.g. Fe(III) sulfate means (Fe3+)2(SO42-)3.

Ionic Half-Equations

You will already be familiar with balanced equations. When the reaction is a redox reaction, we can make some further adjustments.

Ionic half-equations

Ionic half-equations

  • An ionic half equation shows either reduction or oxidation.
    • An example is: O2 + 4e- \rightarrow 2O2-
    • This is the ionic half equation for the reduction of O2 to 2O2-
  • If you have ionic half equations for both a reduction process and an oxidation process, you can add the two to generate a full balanced equation.
An example: TiCl<sub>4</sub>

An example: TiCl4

  • The ionic half equation for the oxidation of Ti \rightarrow Ti4+ is:
    • Ti \rightarrow Ti4+ + 4e-
  • The ionic half equation for the reduction of Cl2 \rightarrow to 2Cl- is:
    • Cl2 + 2e- \rightarrow 2Cl-
  • When adding the two equations together, you must balance the number of electrons on either side so that they cancel out.
    • 2Cl2 + 4e- \rightarrow 4Cl-
    • Ti \rightarrow Ti4+ + 4e-
  • So the full balanced equation is:
    • Ti + 2Cl2 \rightarrow Ti4+ + 4Cl-
Jump to other topics
1

Structure - Models of the Particulate of Matter

2

Structure - Models of Bonding & Structure

3

Structure - Classification of Matter

3.1

The Periodic Table: Classification of Elements

3.2

Periodic Trends

3.3

Group 1 Alkali Metals

3.4

Halogens

3.5

Noble gases, group 18

3.6

Functional Groups: Classification of Organic

3.7

Functional Group Chemistry

3.8

Alkanes

3.9

Alcohols

3.10

Halogenoalkanes

4

Reactivity - What Drives Chemical Reaction?

5

Reactivity - How Much, How Fast & How Far?

6

Reactivity - The Mechanisms of Chemical Change

7

Measurement, Data Processing & Analysis

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