3.9.7

Mass Spectrometry Analysis

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Using a Mass Spectrometer to Identify Molecules

Once a sample has passed through the mass spectrometer, we can analyse the data to identify the molecule.

Mass spectrometry

Mass spectrometry

Mass spectrometry is a technique used to work out:

  • The relative isotopic abundance.
  • Atomic and molecular mass.
  • The structure of a compound.
Spectrum produced

Spectrum produced

  • When the sample has passed through the mass spectrometer, a spectrum is produced by the spectrometer.
  • On this spectrum:
    • The x-axis is mass/charge ratio.
    • The y-axis is % abundance.
Main peak

Main peak

  • The spectrum produces lots of peaks, but the most important is the molecular ion peak.
    • This is the peak of the greatest mass/charge ratio.
  • This represents the mass/charge value of the molecule we are analyzing.
Isotopes

Isotopes

  • Smaller peaks will cluster around the molecular ion peak.
    • These are from the same molecules but with different isotopes in them.
    • The isotopic molecules have different masses and so different mass/charge ratio values.
Fragmentation

Fragmentation

  • Any smaller and significantly lighter peaks in the spectrum are because of fragmentation.
    • The molecule can fragment in the spectrometer.

Calculating Relative Atomic Mass

Once we have the mass spectrum, we can calculate the relative atomic mass.

Relative atomic mass

Relative atomic mass

  • Relative atomic mass is the average weighted mass of an atom relative to carbon-12.
  • The key word to look at here is "average".
  • This is because its value is calculated taking into account all of its isotopes and their relative abundances.
Using the spectrum

Using the spectrum

  • We can use the spectrum to view all the different isotopes and their relative abundance.
  • Isotopic mass is along the x-axis.
  • Isotopic abundance is along the y-axis.
Calculation

Calculation

  • We can then calculate the relative atomic mass since we have all of the isotopic masses and their relative abundances.
  • It is easiest to show how to carry out the calculation with an example - see the next slide.
Example - boron

Example - boron

  • This is the mass spectrum of a sample of elemental boron.
  • Boron has two isotopes, 10B and 11B.
  • You can see from the spectrum that approximately 20% of the boron is 10B and 80% is 11B.
  • You can use this to work out the relative atomic mass:
    • 80% × 11 + 20% × 10 = 10.8
Jump to other topics
1

Physical Chemistry

1.1

Atoms, Molecules & Stoichiometry

1.2

Atomic Structure

1.3

Chemical Bonding

1.4

States of Matter

1.5

Chemical Energetics

1.6

Electrochemistry

1.7

Equilibria

1.8

Partition Coefficient

1.9

Reaction Kinetics

2

Inorganic Chemistry

3

Organic Chemistry & Analysis

3.1

Introduction to Organic Chemistry

3.2

Hydrocarbons

3.3

Halogen Derivatives

3.4

Hydroxy Compounds

3.5

Carbonyl Compounds

3.6

Carboxylic Acids & Derivatives

3.7

Nitrogen Compounds

3.8

Polymerisation

3.9

Analytical Techniques

3.10

Organic Synthesis

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