3.9.7

Mass Spectrometry Analysis

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Using a Mass Spectrometer to Identify Molecules

Once a sample has passed through the mass spectrometer, we can analyse the data to identify the molecule.

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Mass spectrometry

Mass spectrometry is a technique used to work out:

  • The relative isotopic abundance.
  • Atomic and molecular mass.
  • The structure of a compound.
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Spectrum produced

  • When the sample has passed through the mass spectrometer, a spectrum is produced by the spectrometer.
  • On this spectrum:
    • The x-axis is mass/charge ratio.
    • The y-axis is % abundance.
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Main peak

  • The spectrum produces lots of peaks, but the most important is the molecular ion peak.
    • This is the peak of the greatest mass/charge ratio.
  • This represents the mass/charge value of the molecule we are analyzing.
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Isotopes

  • Smaller peaks will cluster around the molecular ion peak.
    • These are from the same molecules but with different isotopes in them.
    • The isotopic molecules have different masses and so different mass/charge ratio values.
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Fragmentation

  • Any smaller and significantly lighter peaks in the spectrum are because of fragmentation.
    • The molecule can fragment in the spectrometer.

Calculating Relative Atomic Mass

Once we have the mass spectrum, we can calculate the relative atomic mass.

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Relative atomic mass

  • Relative atomic mass is the average weighted mass of an atom relative to carbon-12.
  • The key word to look at here is "average".
  • This is because its value is calculated taking into account all of its isotopes and their relative abundances.
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Using the spectrum

  • We can use the spectrum to view all the different isotopes and their relative abundance.
  • Isotopic mass is along the x-axis.
  • Isotopic abundance is along the y-axis.
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Calculation

  • We can then calculate the relative atomic mass since we have all of the isotopic masses and their relative abundances.
  • It is easiest to show how to carry out the calculation with an example - see the next slide.
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Example - boron

  • This is the mass spectrum of a sample of elemental boron.
  • Boron has two isotopes, 10B and 11B.
  • You can see from the spectrum that approximately 20% of the boron is 10B and 80% is 11B.
  • You can use this to work out the relative atomic mass:
    • 80% × 11 + 20% × 10 = 10.8

Jump to other topics

1Physical Chemistry

1.1Atoms, Molecules & Stoichiometry

1.2Atomic Structure

1.3Chemical Bonding

1.4States of Matter

1.5Chemical Energetics

1.6Electrochemistry

1.7Equilibria

1.8Partition Coefficient

1.9Reaction Kinetics

2Inorganic Chemistry

3Organic Chemistry & Analysis

3.1Introduction to Organic Chemistry

3.2Hydrocarbons

3.3Halogen Derivatives

3.4Hydroxy Compounds

3.5Carbonyl Compounds

3.6Carboxylic Acids & Derivatives

3.7Nitrogen Compounds

3.8Polymerisation

3.9Analytical Techniques

3.10Organic Synthesis

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