1.7.6

Weak Acids & Bases

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Weak Acids and Bases

Not all acids and bases fully dissociate in solution.

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Weak acids

  • Weak acids do not fully ionise in solution.
  • For a strong acid, like HCl, the equilibrium for the following equation lies very far to the right:
    • HCl ⇋ H+ + Cl-
  • For a weak acid (e.g. ethanoic acid), the equilibrium lies closer to the middle.
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Weak bases

  • Weak bases behave similarly. They do not fully ionise in solution.
  • So, for weak acids and bases, the concentration of H+ or OH- ions is not just the concentration of the acid or base.
    • This makes it harder to calculate the concentrations in solution.
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Ka

  • We define a new constant as Ka = [H+][A][HA]\frac{[H^+][A^-]}{[HA]}
  • HA refers to the un-ionised acid molecule, and A- refers to the anion remainder after loss of a proton.
    • A large Ka value means that a lot of the acid ionises in solution.
    • A small Ka value means that very little acid ionises in solution.
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pKa

  • Just like pH, we use pKa because Ka values vary a lot.
  • The definition of pKa is:
    • pKa = −log10(Ka)

Calculating the Concentration of Ions

We can use pKa along with pH to calculate the concentrations of varying ions in solution.

Illustrative background for Converting pK<sub>a</sub> to K<sub>a</sub>Illustrative background for Converting pK<sub>a</sub> to K<sub>a</sub> ?? "content

Converting pKa to Ka

  • The definition of pKa is:
    • pKa = -log10(Ka)
  • This can be rearranged into:
    • Ka = 10-pKa
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Calculating [H+] from Ka

  • When you dissolve a weak monoprotic acid in solution, [H+] is always equal to [A-].
  • This means you can simplify Ka into:
    • Ka = [H+]2[HA]\frac{[H^+]^2}{[HA]}
  • But, [HA] is the concentration of the acid added ([HA]0, minus the concentration of the ionised acid), so we can simplify further to:
    • Ka = [H+]2[HA]0[H+]\frac{[H^+]^2}{[HA]_0 - [H^+]}
    • If you know the values of Ka and [HA]0, you can calculate the concentration of H+ ions.
Illustrative background for Calculating [HA] from K<sub>a</sub> and pHIllustrative background for Calculating [HA] from K<sub>a</sub> and pH ?? "content

Calculating [HA] from Ka and pH

  • First, use the definition of pH to calculate the [H+].
  • Next, use [H+] = [A-] to simplify the equation for Ka.
  • Then, rearrange Ka to give [HA]:
    • [HA] = [H+]2Ka\frac{[H^+]^2}{K_a}

Jump to other topics

1Physical Chemistry

1.1Atoms, Molecules & Stoichiometry

1.2Atomic Structure

1.3Chemical Bonding

1.4States of Matter

1.5Chemical Energetics

1.6Electrochemistry

1.7Equilibria

1.8Partition Coefficient

1.9Reaction Kinetics

2Inorganic Chemistry

3Organic Chemistry & Analysis

3.1Introduction to Organic Chemistry

3.2Hydrocarbons

3.3Halogen Derivatives

3.4Hydroxy Compounds

3.5Carbonyl Compounds

3.6Carboxylic Acids & Derivatives

3.7Nitrogen Compounds

3.8Polymerisation

3.9Analytical Techniques

3.10Organic Synthesis

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