3.2.7

Equation of a Perpendicular Bisector

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Perpendicular Bisector of a Chord

We can find the equation of the perpendicular bisector of a chord using the properties of straight lines graphs.

Illustrative background for What is the perpendicular bisector of a chord?Illustrative background for What is the perpendicular bisector of a chord? ?? "content

What is the perpendicular bisector of a chord?

  • The perpendicular bisector of a chord is the perpendicular line that passes through the midpoint of the chord.
  • The perpendicular bisector of a chord always passes through the centre of the circle.
Illustrative background for What is the gradient of the perpendicular bisector?Illustrative background for What is the gradient of the perpendicular bisector? ?? "content

What is the gradient of the perpendicular bisector?

  • We first need to find the gradient of the chord using the equation:
    • mc=y2y1x2x1m_c = \frac{y_2-y_1}{x_2-x_1}
  • Where (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) are the points where the chord meets the circumference.
  • The bisector is perpendicular to the chord, so its gradient mbm_b satisfies:
    • mb×mc=1m_b\times m_c=-1
Illustrative background for What is the equation of the perpendicular bisector?Illustrative background for What is the equation of the perpendicular bisector? ?? "content

What is the equation of the perpendicular bisector?

  • We can then find the equation of the bisector by working out the midpoint of the chord:
    • Midpoint = (x1+x22,y1+y22)(\frac{\small x_1+x_2}{2},\frac{\small y_1+y_2}{2})
  • Finally, we substitute this into the general equation of a straight line with gradient mbm_b to find the yy-intercept cc:
    • y=mbx+cy = m_bx + c
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Example

  • The points A(3,7)A(3,7) and B(6,4)B(6,4) lie on the circumference of a circle.
  • What is the equation of the perpendicular bisector of the chord AB?
Illustrative background for Find the gradient of chordIllustrative background for Find the gradient of chord ?? "content

Find the gradient of chord

  • The gradient of the chord is given by:
    • mc=y2y1x2x1=4763=33=1m_c = \frac{y_2-y_1}{x_2-x_1}=\frac{4-7}{6-3}=-\frac{3}{3}=-1
Illustrative background for Find the gradient of bisectorIllustrative background for Find the gradient of bisector ?? "content

Find the gradient of bisector

  • The gradient of the perpendicular bisector mbm_b satisfies the equation:
    • mb×mc=1m_b\times m_c = -1
    • mb=1mc=1m_b = -\frac{1}{m_c} = 1
Illustrative background for Find the midpoint of chordIllustrative background for Find the midpoint of chord ?? "content

Find the midpoint of chord

  • The midpoint of the chord AB is equal to:
    • midpoint = (x1+x22,y1+y22)=(3+62,7+42)=(4.5,5.5)(\frac{\small x_1+x_2}{2},\frac{\small y_1+y_2}{2}) = (\frac{3+6}{2},\frac{7+4}{2}) = (4.5, 5.5)
Illustrative background for Find the y-intercept of the perpendicular bisectorIllustrative background for Find the y-intercept of the perpendicular bisector ?? "content

Find the y-intercept of the perpendicular bisector

  • Substitute mbm_b and the midpoint into the general equation of a straight line:
    • y=mbx+cy = m_bx+c
    • 5.5=1×4.5+c5.5 = 1\times 4.5 + c
  • Rearranging for cc, we get:
    • c=5.54.5=1c = 5.5 - 4.5 =1
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Final answer

  • So the equation of the perpendicular bisector of the chord AB is:
    • y=x+1y =x + 1

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2.8Partial Fractions (A2 Only)

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