Mass Spectrometry Analysis
Chemistry: Cambridge International A Level, topic 3.9.7
Using a Mass Spectrometer to Identify Molecules
Once a sample has passed through the mass spectrometer, we can analyse the data to identify the molecule.

Mass spectrometry
Mass spectrometry is a technique used to work out:
- The relative isotopic abundance.
- Atomic and molecular mass.
- The structure of a compound.

Spectrum produced
- When the sample has passed through the mass spectrometer, a spectrum is produced by the spectrometer.
- On this spectrum:
- The x-axis is mass/charge ratio.
- The y-axis is % abundance.

Main peak
- The spectrum produces lots of peaks, but the most important is the molecular ion peak.
- This is the peak of the greatest mass/charge ratio.
- This represents the mass/charge value of the molecule we are analyzing.

Isotopes
- Smaller peaks will cluster around the molecular ion peak.
- These are from the same molecules but with different isotopes in them.
- The isotopic molecules have different masses and so different mass/charge ratio values.

Fragmentation
- Any smaller and significantly lighter peaks in the spectrum are because of fragmentation.
- The molecule can fragment in the spectrometer.
Calculating Relative Atomic Mass
Once we have the mass spectrum, we can calculate the relative atomic mass.

Relative atomic mass
- Relative atomic mass is the average weighted mass of an atom relative to carbon-12.
- The key word to look at here is "average".
- This is because its value is calculated taking into account all of its isotopes and their relative abundances.

Using the spectrum
- We can use the spectrum to view all the different isotopes and their relative abundance.
- Isotopic mass is along the x-axis.
- Isotopic abundance is along the y-axis.
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Calculation
- We can then calculate the relative atomic mass since we have all of the isotopic masses and their relative abundances.
- It is easiest to show how to carry out the calculation with an example - see the next slide.

Example - boron
- This is the mass spectrum of a sample of elemental boron.
- Boron has two isotopes, 10B and 11B.
- You can see from the spectrum that approximately 20% of the boron is 10B and 80% is 11B.
- You can use this to work out the relative atomic mass:
- 80% × 11 + 20% × 10 = 10.8
Test yourself on Mass Spectrometry Analysis
What do clustered small peaks around the molecular ion peak represent?