Common-Ion Effect
Chemistry: Cambridge International A Level, topic 1.7.11
Common-Ion Effect
Compared with pure water, the solubility of an ionic compound is less in aqueous solutions containing a common ion. This is an example of a phenomenon known as the common ion effect.

Common-Ion Effect
- Compared with pure water, the solubility of an ionic compound is less in aqueous solutions containing a common ion.
- A common ion is one also produced by dissolution of the ionic compound.
- This is an example of a phenomenon known as the common-ion effect.
- The common-ion effect is a consequence of the law of mass action that may be explained using Le Châtelier’s principle.

Example
- Consider the dissolution of silver iodide:
- AgI(s) ⇌ Ag+(aq)+I−(aq)
- This solubility equilibrium may be shifted left by the addition of either silver(I) or iodide ions.
- This would resulti n the precipitation of AgI and lowered concentrations of dissolved Ag+ and I–.
- In solutions that already contain either of these ions, less AgI may be dissolved than in solutions without these ions.

𝐾sp & common-ion effect
- This effect may also be explained in terms of mass action as represented in the solubility product expression:
- 𝐾sp = [Ag+][I−]
- The mathematical product of silver(I) and iodide ion molarities is constant in an equilibrium mixture regardless of the source of the ions.
- So, an increase in one ion’s concentration must be balanced by a proportional decrease in the other.
Test yourself on Common-Ion Effect
Mg(OH)2 exists the below solubility equilbrium:
Mg(OH)2(s)⇌Mg2+(aq)+2OH−(aq)
What is the effect on the amount of solid Mg(OH)2 when MgCl2 is added to a saturated solution of Mg(OH)2?Mg(OH)2 exists the below solubility equilbrium:
Mg(OH)2(s)⇌Mg2+(aq)+2OH−(aq)
What is the effect on the amount of solid Mg(OH)2 when NaNO3 is added to a saturated solution of Mg(OH)2?Mg(OH)2 exists the below solubility equilbrium:
Mg(OH)2(s)⇌Mg2+(aq)+2OH−(aq)
What is the effect on the amount of solid Mg(OH)2 when KOH is added to a saturated solution of Mg(OH)2?Mg(OH)2 exists the below solubility equilbrium:
Mg(OH)2(s)⇌Mg2+(aq)+2OH−(aq)
What is the effect on the amount of solid Mg(OH)2 when more Mg(OH)2 is added to a saturated solution of Mg(OH)2?