2.8.10

Simultaneous Equations

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Simultaneous Quadratic Equations

You can solve a pair of simultaneous equations where at least one contains a quadratic using the substitution method. This is where you rearrange one of the equations and substitute it into the other equation.

Example

Example

  • Take the pair of simultaneous equations:
    • 2x2 + y = 5
    • 2x + y = 1
  • You can rearrange the second equation to get:
    • y = 1 − 2x
Substitution

Substitution

  • y = 1 − 2x can then be substituted in as an expression for y in
    2x2 + y = 5.
    • This gives 2x2 + 1 − 2x = 5
    • Which can be rearranged to 2x2 − 2x − 4 = 0
Solving for x

Solving for x

  • You can then solve 2x2 − 2x − 4 = 0 to find values of x that satisfies the simultaneous equations.
    • 2x2 − 2x − 4 = 0
    • (2x + 2)(x − 2) = 0
  • Therefore x = −1 and x = 2
Solving for y

Solving for y

  • You then need to find out the values of y by substituting in the values
    x = −1 and x = 2.
Solving for y when x = −1

Solving for y when x = −1

  • 2x + y = 1
  • 2(−1) + y = 1
  • y = 3
    • This means x = −1 and y = 3 is one solution to the simultaneous equations.
Solving for y when x = 2

Solving for y when x = 2

  • 2x + y = 1
  • 2(2) + y = 1
  • y = −3
    • This means x = 2 and y = −3 is the other solution to the simultaneous equations.
Jump to other topics
1

Number

1.1

Using Numbers

1.2

Fractions, Decimals & Percentages

1.3

Powers & Roots

1.4

Accuracy

2

Algebra

2.1

Introduction to Algebra

2.2

Manipulating Algebra

2.3

Proofs & Functions

2.4

Straight Line Graphs

2.5

Common Graphs

2.6

Transformations & Tangents

2.7

Properties of Graphs

2.8

Solving Equations

2.9

Inequalities

2.10

Sequences

3

Ratio

4

Geometry

4.1

Introduction to Geometry

4.2

Triangles & Quadrilaterals

4.3

Transformations

4.4

Circle Basics

4.5

Circle Theorems

4.6

Measurements & Units

4.7

Calculating Area

4.8

Triangle Formulae

4.9

3D Shapes

4.10

Vectors

5

Probability

6

Statistics

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