3.2.7

Equation of a Perpendicular Bisector

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Perpendicular Bisector of a Chord

We can find the equation of the perpendicular bisector of a chord using the properties of straight lines graphs.

What is the perpendicular bisector of a chord?

What is the perpendicular bisector of a chord?

  • The perpendicular bisector of a chord is the perpendicular line that passes through the midpoint of the chord.
  • The perpendicular bisector of a chord always passes through the centre of the circle.
What is the gradient of the perpendicular bisector?

What is the gradient of the perpendicular bisector?

  • We first need to find the gradient of the chord using the equation:
    • mc=y2y1x2x1m_c = \frac{y_2-y_1}{x_2-x_1}
  • Where (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) are the points where the chord meets the circumference.
  • The bisector is perpendicular to the chord, so its gradient mbm_b satisfies:
    • mb×mc=1m_b\times m_c=-1
What is the equation of the perpendicular bisector?

What is the equation of the perpendicular bisector?

  • We can then find the equation of the bisector by working out the midpoint of the chord:
    • Midpoint = (x1+x22,y1+y22)(\frac{\small x_1+x_2}{2},\frac{\small y_1+y_2}{2})
  • Finally, we substitute this into the general equation of a straight line with gradient mbm_b to find the yy-intercept cc:
    • y=mbx+cy = m_bx + c
Example

Example

  • The points A(3,7)A(3,7) and B(6,4)B(6,4) lie on the circumference of a circle.
  • What is the equation of the perpendicular bisector of the chord AB?
Find the gradient of chord

Find the gradient of chord

  • The gradient of the chord is given by:
    • mc=y2y1x2x1=4763=33=1m_c = \frac{y_2-y_1}{x_2-x_1}=\frac{4-7}{6-3}=-\frac{3}{3}=-1
Find the gradient of bisector

Find the gradient of bisector

  • The gradient of the perpendicular bisector mbm_b satisfies the equation:
    • mb×mc=1m_b\times m_c = -1
    • mb=1mc=1m_b = -\frac{1}{m_c} = 1
Find the midpoint of chord

Find the midpoint of chord

  • The midpoint of the chord AB is equal to:
    • midpoint = (x1+x22,y1+y22)=(3+62,7+42)=(4.5,5.5)(\frac{\small x_1+x_2}{2},\frac{\small y_1+y_2}{2}) = (\frac{3+6}{2},\frac{7+4}{2}) = (4.5, 5.5)
Find the y-intercept of the perpendicular bisector

Find the y-intercept of the perpendicular bisector

  • Substitute mbm_b and the midpoint into the general equation of a straight line:
    • y=mbx+cy = m_bx+c
    • 5.5=1×4.5+c5.5 = 1\times 4.5 + c
  • Rearranging for cc, we get:
    • c=5.54.5=1c = 5.5 - 4.5 =1
Final answer

Final answer

  • So the equation of the perpendicular bisector of the chord AB is:
    • y=x+1y =x + 1
Jump to other topics
1

Proof

2

Algebra & Functions

2.1

Powers & Roots

2.2

Quadratic Equations

2.3

Inequalities

2.4

Polynomials

2.5

Graphs

2.6

Functions

2.7

Transformation of Graphs

2.8

Partial Fractions (A2 Only)

3

Coordinate Geometry

4

Sequences & Series

5

Trigonometry

6

Exponentials & Logarithms

7

Differentiation

8

Integration

9

Numerical Methods

10

Vectors

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