2.1.7
Method G - Partial Differences Method
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Partial Differences Method: 753 − 491
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Step 1
- Write out the subtrahend under the minuend, lining up the digits so that the hundreds, tens and ones digits of each number are in the same columns respectively.
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Step 2
- We could work from either right to left or left to right here.
- Starting from the right, we subtract 1 from 3 and write the difference in the ones column. 3 − 1 = 2.
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Step 3
- Subtract 9 from 5 and write the difference in the tens column.
- 5 − 9 = −4.
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Step 4
- Unlike in other methods, it’s fine to write a negative number in the bottom row.
- Subtract 4 from 7 and write the difference in the hundreds column.
- 7 − 4 = 3.
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Step 5
- Now calculate the value of the difference.
- Reading off the bottom row, we have 300 − 40 + 2.
- 300 − 40 + 2 = 262
- So 753 − 491 = 262
1Course Overview
1.1Course Structure & Commonly Asked Questions
2Subtraction Methods
2.1Subtraction Methods
2.1.1Method A - Decomposition Method2.1.2Method B - Equal Addition Method2.1.3Method C - Expanded Form Method2.1.4Method D - Partitioning Method2.1.5Method E - Counting-Up Method2.1.6Method F - Constant Difference Method2.1.7Method G - Partial Differences Method2.1.8Method H - Complementary Method2.1.9Method I - Nines Complement Method
Jump to other topics
1Course Overview
1.1Course Structure & Commonly Asked Questions
2Subtraction Methods
2.1Subtraction Methods
2.1.1Method A - Decomposition Method2.1.2Method B - Equal Addition Method2.1.3Method C - Expanded Form Method2.1.4Method D - Partitioning Method2.1.5Method E - Counting-Up Method2.1.6Method F - Constant Difference Method2.1.7Method G - Partial Differences Method2.1.8Method H - Complementary Method2.1.9Method I - Nines Complement Method
Practice questions on Method G - Partial Differences Method
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